A conductor moving in the magnetic field $B$ and the induced current is $I$. If the magnetic field is…
A conductor moving in the magnetic field $B$ and the induced current is $I$. If the magnetic field is doubled the induced current will
remain the same
be half
be doubled
be four times
Solution
Given, initial magnetic field $=B$
Initial induced current $=I$
Final magnetic field, $B^{\prime}=2 B$
Final current $=I^{\prime}$
Since, emf, $\varepsilon=B l v \sin \theta=I R$
where, $B$ is magnetic field,
$l$ is length of conductor,
$v$ is velocity,
$I$ is current,
and $R$ is resistance.
$\therefore \quad I \propto B$
Hence, if $B$ doubled current $I$ also doubled.