A conductivity cell dipped in 0.05 M KCl has resistance 600 ohm . If conductivity is $0.0012…

A conductivity cell dipped in 0.05 M KCl has resistance 600 ohm . If conductivity is $0.0012 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$. What is the value of cell constant?
  1. $0.50 \mathrm{~cm}^{-1}$
  2. $0.72 \mathrm{~cm}^{-1}$
  3. $1.5 \mathrm{~cm}^{-1}$
  4. $2.0 \mathrm{~cm}^{-1}$

Solution

$\begin{aligned} & \text { Conductivity }(\mathrm{k})=\frac{\text { Cell constant }}{\mathrm{R}} \\ \therefore \quad & \text { Cell constant }=\mathrm{k} \times \mathrm{R} \\ = & 0.0012 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1} \times 600 \mathrm{ohm}=0.72 \mathrm{~cm}^{-1}\end{aligned}$

Asked in: MHT CET 2024 (10 May Shift 1)

Practice more Electrochemistry questions on Aicharya