A conducting wire of length l , area of crosssection A and electric resistivity ρ is connected between…

A conducting wire of length l, area of crosssection A and electric resistivity ρ is connected between the terminals of a battery. A potential difference V is developed between its ends, causing an electric current. If the length of the wire of the same material is doubled and the area of cross-section is halved, the resultant current would be___

  1. 14VAρl
  2. 34VAρl
  3. 14ρlVA
  4. 4VAρl

Solution

As per the question 

Resistance =ρ2lA/2=4ρl A

Current =VR=VA4ρl

Asked in: JEE Main 2021 (16 Mar Shift 1)

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