A conducting sphere of radius $\mathrm{R}$ is given a charge Q. The electric potential and the electric…

A conducting sphere of radius $\mathrm{R}$ is given a charge Q. The electric potential and the electric field at the centre of the sphere respectively are:
  1. 0 and $\frac{\mathrm{Q}}{4 \pi \varepsilon_{0} \mathrm{R}^{2}}$
  2. $\frac{\mathrm{Q}}{4 \pi \varepsilon_{0} \mathrm{R}}$ and 0
  3. $\frac{\mathrm{Q}}{4 \pi \varepsilon_{0} \mathrm{R}}$ and $\frac{\mathrm{Q}}{4 \pi \varepsilon_{0} \mathrm{R}^{2}}$
  4. Both are 0

Solution

Due to conducting sphere At centre, electric field $\mathrm{E}=0$
And electric potential $\mathrm{V}=\frac{\mathrm{Q}}{4 \pi \in_{0} \mathrm{R}}$

Asked in: JEE Mains - Electrostatics - Test 4

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