A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field B exists…


A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field B exists into the page. The bar starts to move from the vertex at time $t=0$ with a constant velocity. If the induced EMF is $\mathrm{E} \propto \mathrm{t}^{\mathrm{n}}$, then value of n is _.

Solution

As the bar moves without change in orientation, the length of bar will be proportional to its distance from the vertex.
i.e. $I=c(v t)$
$\begin{aligned}
& \text { induced emf } E=B / v \\ & =c B v^2 t
\end{aligned}$
$\Rightarrow n=1$

Asked in: JEE Main 2025 (28 Jan Shift 2)

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