A compound 'X' on treatment with Br $/ \mathrm{NaOH}$, provided $\mathrm{C}_{3} \mathrm{H}_{9} \mathrm{~N},$…
- $\mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{NHCH}_{3}$
- $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCH}_{2} \mathrm{NH}_{2}$
- $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CONH}_{2}$
- $\mathrm{CH}_{3} \mathrm{CON}\left(\mathrm{CH}_{3}\right)_{2}$
Asked in: JEE Main 2019 (11 Jan Shift 2)