A compound H 2 X with molar weight of 80g is dissolved in a solvent having density of 0.4   g m l…

A compound H2X with molar weight of 80g is dissolved in a solvent having density of 0.4 gml–1 . Assuming no change in volume upon dissolution, the molality of a 3.2 molar solution is

Solution

Here, Vsolution≈Vsolvent
Since, in 1l solution, 3.2 moles of solute are present,
So, 1l solution ≈1l solvent (d = 0.4g/ml) ≈ 0.4 kg
So, molality (m) =Moles of soluteMass of solvent (kg)=3.20.4=8

Asked in: JEE Advanced 2014 (Paper 1)

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