A complex number $z$ among the following which satisfy $z^3+27 i=0$ is

A complex number $z$ among the following which satisfy $z^3+27 i=0$ is
  1. $(3 \sqrt{3}-3 i) / 2$
  2. $-3 i$
  3. $(3 \sqrt{3}+3 i) / 2$
  4. $(-3 \sqrt{3}+3 i) / 2$

Solution

Given, $z^3+27 i=0$ $\begin{aligned} & \Rightarrow \quad z^3-(3 i)^3=0 \\ & \Rightarrow \quad(z-3 i)\left(z^2+3 z i-9\right)=0\end{aligned}$ If $\quad z-3 i=0 \Rightarrow z=3 i$ If $z^2+3 z i-9=0$ $\begin{aligned} & \Rightarrow \quad z=\frac{-3 i \pm \sqrt{-9+36}}{2}=\frac{-3 i \pm 3 \sqrt{3}}{2} \\ & \Rightarrow \quad z=\frac{3 \sqrt{3}-3 i}{2}, \frac{-3 \sqrt{3}-3 i}{2}\end{aligned}$

Asked in: AP EAMCET 2022 (08 Jul Shift 2)

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