A company dissolves ' x ' amount of CO 2 at 298   K in 1 litre of water to prepare soda water.…

A company dissolves 'x' amount of CO2 at 298 K in 1 litre of water to prepare soda water. X=×10-3 g. (nearest integer)

(Given: partial pressure of CO2 at 298 K=0.835 bar. Henry's law constant for CO2 at 298 K=1.67 kbar. Atomic mass of H,C and O is 1,12, and 6 g mol-1, respectively)

Solution

$P_{\text{gas}} = K_H \cdot X_{\text{gas}}$ $\begin{aligned} 10^{-3} \cdot X_{0.835} &= \frac{n_{CO_2}}{n_{CO_2} + 55.5} \\ 10^{-3} \cdot X_{0.5} &= \frac{n_{CO_2}}{n_{CO_2} + 55.5} \\ \frac{n_{CO_2}}{55.5} &= 0.5 \cdot 10^{-3} \\ n_{CO_2} &= 27.75 \cdot 10^{-3} \\ W_{CO_2} &= 27.75 \cdot 10^{-3} \cdot 44 = 1221 \cdot 10^{-3} \, g \end{aligned}$

Asked in: JEE Main 2022 (24 Jun Shift 2)

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