A commercial sample of \(\mathrm{H}_2 \mathrm{O}_2\) marked as 100 volume hydrogen peroxide means
- \(1 \mathrm{~mL}\) of \(\mathrm{H}_2 \mathrm{O}_2\) will give \(100 \mathrm{~mL}\) of \(\mathrm{O}_2\) at STP
- \(1 \mathrm{~L}\) of \(\mathrm{H}_2 \mathrm{O}_2\) will give \(100 \mathrm{~mL}\) of \(\mathrm{O}_2\) at STP
- \(1 \mathrm{~L}\) of \(\mathrm{H}_2 \mathrm{O}_2\) will give \(22.4 \mathrm{LO}_2\) at STP
- \(1 \mathrm{~mL}\) of \(\mathrm{H}_2 \mathrm{O}_2\) will give 1 mole of \(\mathrm{O}_2\) at STP
Solution
Asked in: AP EAMCET 2020 (18 Sep Shift 2)