A coin is tossed twice. Probability of getting exactly two Heads is:
A coin is tossed twice. Probability of getting exactly two Heads is:
- $\dfrac{1}{4}$
- $\dfrac{1}{2}$
- $\dfrac{3}{4}$
- $\dfrac{1}{3}$
Solution
Sample space $= \{HH, HT, TH, TT\}$. Two Heads $= \{HH\}$. $P = \dfrac{1}{4}$.
Asked in: IMO
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