A coil of wire of radius r has 600 turns and self-inductance of 108 mH . The self-inductance of a coil with the same radius and 500 turns is

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Aicharya · Accepted Answer

Given L 1 = 108 m H , N 1 = 600 t u r n s , N 2 = 500 t u r n s a n d L 2 = ? By self - inductance of a plane coil L 1 = μ 0 π N 1 2 a 1 2 ......(i) L 2 = μ 0 π N 2 2 a 2 2 ......(ii) From the equations (i) and (ii), we get L 1 L 2 = N 1 N 2 2 ∵ a 1 = a 2 108 L 2 = 600 500 2 L 2 = 108 × 25 36 L 2 = 3 × 25 = 75 m H ^

A coil of wire of radius r has 600 turns and self-inductance of 108 mH . The self-inductance of a coil with…

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