A coil of resistance $400 \Omega$ is placed in a magnetic field. If the magnetic flux $\phi(\mathrm{Wb})$…
- $0.5 \mathrm{~A}$
- $0.1 \mathrm{~A}$
- $2 \mathrm{~A}$
- $1 \mathrm{~A}$
Solution
$\begin{aligned}
E & =\left|-\frac{d \phi}{d t}\right|_{t=2} \\
& =|100 t|_{t=2}=200 \mathrm{~V}
\end{aligned}$
Current in the coil
$\begin{aligned}
i & =\frac{E}{R}=\frac{200}{400} \\
& =\frac{1}{2}=0.5 \mathrm{~A}
\end{aligned}$
Asked in: NEET 2012 (Screening)
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