A coil of circular cross-section having 1000 turns and $4 \mathrm{~cm}^2$ face area is placed with its axis…

A coil of circular cross-section having 1000 turns and $4 \mathrm{~cm}^2$ face area is placed with its axis parallel to a magnetic field which decreases by $10^{-2} \mathrm{~Wb}$ $\mathrm{m}^{-2}$ in $0.01 \mathrm{~s}$. The e.m.f. induced in the coil is:
  1. $400 \mathrm{mV}$
  2. $200 \mathrm{mV}$
  3. $4 \mathrm{mV}$
  4. $0.4 \mathrm{mV}$

Solution

Given: No. of turns $N=1000$ Face area, $A=4 \mathrm{~cm}^2=4 \times 10^{-4} \mathrm{~m}^2$ Change in magnetic field, $ \Delta \mathrm{B}=10^{-2} \mathrm{wbm}^{-2} $ Time taken, $t=0.01 \mathrm{~s}=10^{-2} \mathrm{sec}$ Emf induced in the coil $e=$ ? Applying formula, Induced emf, $e=\frac{-d \phi}{d t}$ $ \begin{aligned} &=N\left(\frac{\Delta B}{\Delta t}\right) A \cos \theta \\ &=\frac{1000 \times 10^{-2} \times 4 \times 10^{-4}}{10^{-2}}=400 \mathrm{mV} \end{aligned} $

Asked in: JEE Main 2014 (11 Apr Online)

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