A coil is placed perpendicular to a magnetic field of 5000 T . When the field is changed to 3000 T in 2 s ,…

A coil is placed perpendicular to a magnetic field of 5000 T. When the field is changed to 3000 T in 2 s, an induced emf of 22 V is produced in the coil. If the diameter of the coil is 0.02 m, then the number of turns in the coil is:
  1. 7
  2. 70
  3. 35
  4. 140

Solution

Average induced EMF is given by, ε=Nϕt

Also, change in flux ϕ=(B)A

Given: Bi=5000 T,

Bf=3000 T

d=0.02 m r=d2=0.01 m

Hence, 

ϕ=(B)A

=2000π0.012=0.2π

EMF, ε=Nϕt22=N0.2π2

N=70

Asked in: JEE Main 2024 (31 Jan Shift 1)

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