A coil has an inductance of 2   H and resistance of 4   Ω . A 10   V is applied across…

A coil has an inductance of 2 H and resistance of 4 Ω. A 10 V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be _____ ×10-2 J

Solution

The data given is 

L=2 HR=4 ΩV=10 V

Using Ohm's law, V=IR,

 I=10 V4 Ω=52 A

The energy of an inductor is given by 
      E=12LI2=12×2×254=625×10-2 J

Asked in: JEE Main 2023 (11 Apr Shift 2)

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