A $100 \mathrm{mH}$ coil carries a current of $1 \mathrm{~A}$. Energy stored in the form of magnetic field is

A $100 \mathrm{mH}$ coil carries a current of $1 \mathrm{~A}$. Energy stored in the form of magnetic field is
  1. $0.025 \mathrm{~J}$
  2. $0.050 \mathrm{~J}$
  3. $0.075 \mathrm{~J}$
  4. $0.100 \mathrm{~J}$

Solution

Energy stored in an inductor $\mathrm{E}=\frac{1}{2} \mathrm{LI}^2$ $\begin{aligned} & =\frac{1}{2} \times\left(100 \times 10^{-3}\right) \times 1 \\ & =0.05 \mathrm{~J} \end{aligned}$

Asked in: MHT CET 2023 (10 May Shift 2)

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