A clock has $75 \mathrm{~cm}, 60 \mathrm{~cm}$ long second hand and minute hand respectively. In 30 minutes duration the tip of second hand will travel $x$ distance more than the tip of minute hand. The value of $x$ in meter is nearly (Take $\pi=3.14$ ) :

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Aicharya · Accepted Answer

$\begin{aligned} \mathrm{x}_{\min }= & \pi 	imes \mathrm{r}_{\min } \ = & \pi 	imes \frac{60}{100} \mathrm{~m} . \ \mathrm{x}_{	ext {second }} & =30 	imes 2 \pi 	imes \mathrm{r}_{	ext {second }} \ & =30 	imes 2 \pi 	imes \frac{75}{100} \ \mathrm{x}= & \mathrm{x}_{	ext {second }}-\mathrm{x}_{\min } \ = & 139.4 \mathrm{~m}\end{aligned}$

A clock has $75 \mathrm{~cm}, 60 \mathrm{~cm}$ long second hand and minute hand respectively. In 30 minutes…

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