A circular platform is mounted on a vertical frictionless axle. Its radius is r = 2   m and its moment of inertia I = 200   k g   m 2 . It is initially at rest. A 70   kg man stands on the edge of the platform and begins to walk along the edge at speed v 0 = 1 . 0   m…

Question

A circular platform is mounted on a vertical frictionless axle. Its radius is r = 2 &#160; m and its moment of inertia I = 200 &#160; k g &#160; m 2 . It is initially at rest. A 70 &#160; kg man stands on the edge of the platform and begins to walk along the edge at speed v 0 = 1 . 0 &#160; m &#160; s - 1 , relative to the ground. The angular velocity of the platform is 0.7 &#160; r a d &#160; s - 1 . When the man has walked once around the platform so that he is at his original position on it, his angular displacement relative to the ground is

Aicharya · Accepted Answer

Angular velocity of the man relative to the platform is

ω_{r} = ω + \frac{v_{0}}{r} = 0.7 + \frac{1}{2} = 1.2 r a d s^{- 1}

Time taken by the man to complete one revolution is

T = \frac{2 π}{ω_{r}} = \frac{2 π}{1.2} s

Angular displacement of the man w.r.t. ground is

θ = ω_{0} T = \frac{v_{0} T}{r} = \frac{1}{2} (\frac{2 π}{1.2}) = \frac{5}{6} π r a d

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A circular platform is mounted on a vertical frictionless axle. Its radius is r = 2   m and its moment…

Solution

A circular platform is mounted on a vertical frictionless axle. Its radius is r = 2 &#160; m and its moment…

Solution

A circular platform is mounted on a vertical frictionless axle. Its radius is r = 2 m and its moment…