A circular loop of radius 0 . 3   cm lies parallel to a much bigger circular loop of radius 20  …

A circular loop of radius 0.3 cm lies parallel to a much bigger circular loop of radius 20 cm. The centre of the small loop is on the axis of the bigger loop. The distance between their centres is15 cm. If a current of 2.0 A flows through the smaller loop, then the flux linked with a bigger loop is:
  1. 3.3×10-11weber
  2. 6.6×10-9weber
  3. 9.1×10-11weber
  4. 6×10-11weber

Solution

ϕ2=B1×A2=μ0IR122(R12+x2)32×πR22

= μ0(2)(20×10−2)22[(0.2)2+(0.15)2]32×π(0.3×10−2)

On solving

= 9.216 × 1 0 - 1 1

≈ 9.2 × 1 0 - 1 1  weber

Asked in: JEE Main 2013 (07 Apr)

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