A circular loop made of thin copper wire of mass ' $\mathrm{m}$ ' is placed in a uniform magnetic field such…
- $\frac{4 \pi \mathrm{m}}{\rho \mathrm{d}}\left(\frac{\mathrm{dB}}{\mathrm{dt}}\right)$
- $\frac{4 \mathrm{~m}}{\pi \rho \mathrm{d}}\left(\frac{\mathrm{dB}}{\mathrm{dt}}\right)$
- $\frac{\pi \mathrm{m}}{4 \rho \mathrm{d}}\left(\frac{\mathrm{dB}}{\mathrm{dt}}\right)$
- $\frac{\mathrm{m}}{4 \pi \rho \mathrm{d}}\left(\frac{\mathrm{dB}}{\mathrm{dt}}\right)$
Solution
Asked in: AP EAMCET 2017 (24 Apr Shift 1)
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