A circular arc of radius 'r' carrying current 'I' subtends on angle $\frac{\pi}{16}$ at its centre. The…
A circular arc of radius 'r' carrying current 'I' subtends on angle $\frac{\pi}{16}$ at its centre. The radius of a metal wire is uniform. The magnetic induction at the centre of circular arc is
$\frac{\mu_{0} \text { I }}{16 r}$
$\frac{\mu_{0} \text { I }}{32 r}$
$\frac{\mu_{0} I}{64 r}$
$\frac{\mu_{0} \text { I }}{8 r}$
Solution
$B_{a t 0}=\frac{\mu_{0} I}{4 \pi r}\left(\frac{\pi}{1}\right.)$
$B_{a t 0}=\frac{\mu_{0} I}{64 r}$
