A circle cuts off positive intercepts 5 and 6 on the $x$ and $y$ axes respectively, and passes through the…

A circle cuts off positive intercepts 5 and 6 on the $x$ and $y$ axes respectively, and passes through the origin. Then the equation of the circle is
  1. $x^2+y^2+5 x+6 y=0$
  2. $x^2+y^2-5 x+6 y=0$
  3. $x^2+y^2-5 x-6 y=0$
  4. $x^2+y^2+5 x-6 y=0$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2020 (07 Oct Special)

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