A charged particle $q$ is placed at the centre $O$ of cube of length $L$ (A B C D E F G H). Another same…
A charged particle $q$ is placed at the centre $O$ of cube of length $L$ (A B C D E F G H). Another same charge $q$ is placed at a distance $L$ from $O$. Then the electric flux through $A B C D$ is
$q / 4 \pi \epsilon_0 L$
zero
$\mathrm{q} / 2\pi \epsilon_0 L$
$q / 3 \pi \epsilon_0 L$
Solution
The flux for both the charges exactly cancels the effect of each other
