A charged particle having drift velocity of 7.5 × 10 − 4 m s − 1 in an electric field of 3 × 10 − 10 V m − 1…

A charged particle having drift velocity of 7.5×10−4 m s−1 in an electric field of 3×10−10 V m−1, has a mobility in m2 V–1 s–1 of:
  1. 2.5×106
  2. 2.5×10–6
  3. 2.25×10–15
  4. 2.25×1015

Solution

Drift velocity is given by, vd=E×μ

⇒μ=vdE=7.5×10−43×10−10

μ=2.5×106 m2 V-1 s-1

Asked in: NEET 2020 (Phase 1)

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