A charge q is placed at one corner of a cube as shown in figure. The flux of electrostatic field E →…

A charge q is placed at one corner of a cube as shown in figure. The flux of electrostatic field E→ through the shaded area is:

  1. q8ε0
  2. q24ε0
  3. q48ε0
  4. q4ε0

Solution

flux through cube =q8ϵ0

flux through surfaces ABEH,ADGH,ABCD will be zero

ϕEFGH=ϕDCFG=ϕEBCF=13q8ϵ0

=q24ϵ0

Asked in: JEE Main 2021 (25 Feb Shift 2)

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