A charge of magnitude ' $2 \mathrm{e}$ ' and mass ' $4 \mathrm{~m}$ ' is moving in an electric Field E. The…
A charge of magnitude ' $2 \mathrm{e}$ ' and mass ' $4 \mathrm{~m}$ ' is moving in an electric Field E. The acceleration imparted to the above charge is
$\frac{2 \mathrm{~m}}{3 \mathrm{Ee}}$
$\frac{E e}{2 m}$
$\frac{2 \mathrm{Ee}}{3 \mathrm{~m}}$
$\frac{3 \mathrm{~m}}{2 \mathrm{Ee}}$
Solution
Force, $\mathrm{F}=$ charge $\times$ Electric field $=2 \mathrm{eE}$
$\text { Acceleration }=\frac{\text { Force }}{\text { Mass }}=\frac{2 \mathrm{eE}}{4 \mathrm{~m}}=\frac{\mathrm{eE}}{2 \mathrm{~m}}$