A charge ' $q$ ' moves with velocity ' $v$ ' through electric (E) as well as magnetic field (B). Then the…
- $\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})$
- $\mathrm{q}(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{v}})$
- $\mathrm{q}(\overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{v}})$
- $\overrightarrow{\mathrm{qE}}+\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})$
Solution
Asked in: MHT CET 2023 (09 May Shift 2)
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