A charge ' $q$ ' is spread uniformly over an isolated ring of radius ' $R$ '. The ring is rotated about its…

A charge ' $q$ ' is spread uniformly over an isolated ring of radius ' $R$ '. The ring is rotated about its natural axis with angular speed $\omega$. The magnetic dipole moment of the ring is
  1. $\frac{q \omega R}{2}$
  2. $q \omega R^2$
  3. $\frac{q \omega R^2}{2}$
  4. $\frac{q \omega}{2 R}$

Solution


$\begin{aligned} & \text { Magnetic moment, } \\ & M=\left(\frac{q}{2 m}\right) L \\ & =\left(\frac{q}{2 m}\right)\left(m R^2\right) \omega \\ & =\frac{q \omega R^2}{2}\end{aligned}$

Asked in: AP EAMCET 2024 (23 May Shift 1)

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