A charge $Q$ is enclosed by a Gaussian spherical surface of radius $R$. If the radius is doubled, then the…
A charge $Q$ is enclosed by a Gaussian spherical surface of radius $R$. If the radius is doubled, then the outward electric flux will
be reduced to half
remain the same
be doubled
increase four times
Solution
Total flux $=\frac{\text { Net enclosed charge }}{\varepsilon_0}$
Hence, we can say the electric flux depends only on net enclosed charge by surface.
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