A certain mass of hydrogen is changed to helium by the process of fusion. The mass defect in fusion reaction…

A certain mass of hydrogen is changed to helium by the process of fusion. The mass defect in fusion reaction is $0.02866 \mathrm{u}$. The energy liberated per $u$ is (given $1 \mathrm{u}=931 \mathrm{MeV}$ )
  1. $2.67 \mathrm{MeV}$
  2. $26.7 \mathrm{MeV}$
  3. $6.675 \mathrm{MeV}$
  4. $13.35 \mathrm{MeV}$

Solution

Here, $\Delta m=0.02866 U$ $\begin{aligned} & \therefore \text { Energy liberated } \\ & =\frac{0.02866 \times 931}{4}=\frac{26.7}{4} \mathrm{MeV}=6.675 \mathrm{MeV} \end{aligned}$

Asked in: NEET 2013 (All India)

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