A cell of emf $\varepsilon$ and internal resistance $r$ is connected across a variable load resistance $R$. The graph drawn between its terminal voltage and resistance $R$ is

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Aicharya · Accepted Answer

According to the question, circuit diagram of a cell is given below,

As, $I r=E-V \Rightarrow \frac{V}{R} r=E-V$ $\Rightarrow V\left[1+\frac{r}{R}\right]=E \Rightarrow V=\frac{E}{R+r} \cdot R$ General equation of a straight line passing through the origin, $y=m x$ Here, $y=V, m=\frac{E}{R+r}=$ slope of the line and $\quad x=R$ As this line is passing through the origin and has a slope which reduces as $R$ increases. Hence, the graph is

A cell of emf \(\varepsilon\) and internal resistance \(r\) is connected across a variable load resistance…

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