A cell can be balanced against $110 \mathrm{~cm}$ and $100 \mathrm{~cm}$ of potentiometer wire, respectively…

A cell can be balanced against $110 \mathrm{~cm}$ and $100 \mathrm{~cm}$ of potentiometer wire, respectively with and without being short circuited through a resistance of $10 \Omega$. Its internal resistance is
  1. Zero
  2. $1.0 \mathrm{ohm}$
  3. $0.5 \mathrm{ohm}$
  4. $2.0 \mathrm{ohm}$

Solution

Internal resistance $=\left(\frac{110}{100}-1\right) \times 10 \Omega$

Asked in: NEET 2008 (Mains)

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