A carrier wave of peak voltage $15 \mathrm{~V}$ is used to transmit a message signal. If the modulation…
A carrier wave of peak voltage $15 \mathrm{~V}$ is used to transmit a message signal. If the modulation index is $60 \%$, then the peak voltage of the modulating signal is
$3 \mathrm{~V}$
$6 \mathrm{~V}$
$9 \mathrm{~V}$
$12 \mathrm{~V}$
Solution
The peak voltage for the modulating signal is
$\mathrm{m}=\frac{\mathrm{A}_{\mathrm{m}}}{\mathrm{A}_{\mathrm{C}}} ; \mathrm{A}_{\mathrm{m}}=\mathrm{mA}_{\mathrm{C}}=0.60 \times 15=9 \mathrm{~V}$