A Carnot's engine works like a refrigerator between 250   K and 300   K . It receives 500…

A Carnot's engine works like a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at a lower temperature. The amount of work done in each cycle to operate the refrigerator is,
  1. 772 J
  2. 420 J
  3. 2100 J
  4. 2520 J

Solution

η=1− T 2 T 1 , efficiency =1-T2T1=WQ2+W⇒1-250300=WQ2+W =420 J

Asked in: JEE Main 2018 (15 Apr)

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