A Carnot engine having an efficiency of 1 10 is being used as a refrigerator. If the work done on the…

A Carnot engine having an efficiency of 110 is being used as a refrigerator. If the work done on the refrigerator is 10 J, the amount of heat absorbed from the reservoir at a lower temperature is
  1. 99 J
  2. 100 J
  3. 1 J
  4. 90 J

Solution

For Carnot engine using as refrigerator
W=Q2T1T2-1
It is given η=110⇒η=1-T2T1⇒T2T1=910
So ,Q2=90 J as W=10 J

Asked in: JEE Main 2020 (08 Jan Shift 2)

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