A Carnot engine has the same efficiency between 800 K and 500 K . and $x\gt600 \mathrm{~K}$ and 600 K . The value of ' $x$ ' is

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Aicharya · Accepted Answer

$\eta_1=1-\frac{T_2}{T_1}=1-\frac{500}{800}=\frac{3}{8} \Rightarrow \eta_2=1-\frac{600}{x}$ $	herefore \quad \eta_1=\eta_2$ $\Rightarrow 1-\frac{600}{x}=\frac{3}{8} \Rightarrow \frac{600}{x}=\frac{5}{8}$ $	herefore x=960 K$

A Carnot engine has the same efficiency between 800 K and 500 K . and $x\gt600 \mathrm{~K}$ and 600 K . The…

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