A car runs at a constant speed on a circular track of radius $100 \mathrm{~m}$, taking 62.8 seconds for…
- $10 \mathrm{~m} / \mathrm{s}, 0$
- 0,0
- $0,10 \mathrm{~m} / \mathrm{s}$
- $10 \mathrm{~m} / \mathrm{s}, 10 \mathrm{~m} / \mathrm{s}$
Solution
$\begin{aligned}
& =2 \pi r \\
& \therefore \text { Average speed }=\frac{\text { Totaldistance }}{\text { Total time }} \\
& \Rightarrow \quad \frac{2 \pi r}{t}=\frac{2 \times 3.14 \times 100}{62.8} \\
& =10 \mathrm{~m} / \mathrm{s}
\end{aligned}$
Displacement in one revolution is zero.
$\begin{aligned}
\therefore \text { Average Velocity }= & \frac{\text { Net displacement }}{\text { True }} \\
& =\frac{0}{t}=0
\end{aligned}$
Asked in: NEET 2006
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