A car of mass $1500 \mathrm{~kg}$ is moving with $20 \mathrm{~ms}^{-1}$ velocity. If the breaks are applied…

A car of mass $1500 \mathrm{~kg}$ is moving with $20 \mathrm{~ms}^{-1}$ velocity. If the breaks are applied it comes to rest in 5 seconds, then the retarding force is
  1. $9000 \mathrm{~N}$
  2. $6000 \mathrm{~N}$
  3. $12000 \mathrm{~N}$
  4. $3000 \mathrm{~N}$

Solution

Retarding force $\mathrm{F}_{\text {retard }}=\frac{\mathrm{m} \Delta \mathrm{v}}{\Delta \mathrm{t}}=\frac{1500 \times(0-20)}{5}$ $ =\frac{1500 \times-20}{5}=-6000 \mathrm{~N} $

Asked in: AP EAMCET 2023 (15 May Shift 1)

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