A $1 \mu \mathrm{~F}$ capacitor is charged to 50 V and is then discharged through 10 mH inductor of…
A $1 \mu \mathrm{~F}$ capacitor is charged to 50 V and is then discharged through 10 mH inductor of negligible resistance. The maximum current in the inductor is
0.5 A
1.5 A
1 A
0.15 A
Solution
Energy stored in capacitor $=\frac{1}{2} \mathrm{CV}^2$
For maximum current energy stored in inductor, $\frac{1}{2} \mathrm{CV}^2=\frac{1}{2} \mathrm{LI}_0^2$.
$\mathrm{I}_0=$ Maximum current
$\mathrm{I}_0^2=\frac{\mathrm{CV}^2}{\mathrm{~L}}=\frac{10^{-6} \times 50 \times 50}{10 \times 10^{-3}}$
$=25 \times 10^{-2}$
$\mathrm{I}_0=\sqrt{25 \times 10^{-2}}$
$\mathrm{I}_0=0.5 \mathrm{~A}$