A bus travelling the first one third distance at a speed of $10 \mathrm{~km} / \mathrm{h}$, the next one third at $20 \mathrm{~km} / \mathrm{h}$ and the last one-third at $60 \mathrm{~km} / \mathrm{h}$. The average speed of the bus is

Question

Aicharya · Accepted Answer

Average speed $=\frac{\mathrm{s}}{\frac{\mathrm{s} / 3}{10}+\frac{\mathrm{s} / 3}{20}+\frac{\mathrm{s} / 3}{60}}=\frac{\mathrm{s}}{\mathrm{s} / 18}=18 \mathrm{~km} / \mathrm{h}$ .

A bus travelling the first one third distance at a speed of $10 \mathrm{~km} / \mathrm{h}$, the next one…

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