A bullet of mass $20 \mathrm{~g}$ moving with a velocity of $200 \mathrm{~m} / \mathrm{s}$ strikes a target…

A bullet of mass $20 \mathrm{~g}$ moving with a velocity of $200 \mathrm{~m} / \mathrm{s}$ strikes a target and is brought to rest in $\left(\frac{1}{50}\right)^{\text {th }}$ of a second. The impulse and average force of impact are respectively
  1. $2 \mathrm{Ns}, 100 \mathrm{~N}$
  2. $4 \mathrm{Ns}, 100 \mathrm{~N}$
  3. $2 \mathrm{Ns}, 200 \mathrm{~N}$
  4. $4 \mathrm{Ns}, 200 \mathrm{~N}$

Solution

When a bullet of mass $m$ moving with a velocity $v$ strikes a target and is brought to rest in time $t$, the impulse $J$ and average force $F_{\text {avg }}$ are calculated using the following relations: 1. Impulse is the change in momentum: $J=\Delta p=m \times v$ 2. Average force is given by the impulse divided by time: $F_{\mathrm{avg}}=\frac{J}{t}=\frac{m \times v}{t}$ Given the correct values from the options, Answer (4) is correct.

Asked in: MHT CET 2020 (12 Oct Shift 2)

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