A bullet of 10   g leaves the barrel of gun with a velocity of 600   m   s - 1 . If the…

A bullet of 10 g leaves the barrel of gun with a velocity of 600 m s-1. If the barrel of gun is 50 cm long and mass of gun is 3 kg, then value of impulse supplied to the gun will be:

  1. 6 N s
  2. 3 N s
  3. 36 N s
  4. 12 N s

Solution

The formula to calculate the impulse J on the gun is given by

J=mv-u   ...1

where, m is the mass, u is the initial velocity and v is the final velocity of the bullet.

Substitute the values of the known parameters into equation (1) to calculate the required impulse.

J=10 g×1 kg1000 g×600-0 m s-1= 6 N s

Asked in: JEE Main 2023 (13 Apr Shift 1)

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