A bulb and a capacitor are connected in series across an ac supply. A dielectric is then placed between the…
- increases
- decreases
- remains same
- becomes zero
Solution

$Z=\sqrt{R^2+X_C^2} \& X_C=\frac{1}{W C}$ due to dielectric $\mathrm{C} \uparrow \Rightarrow \mathrm{X}_{\mathrm{C}} \downarrow \Rightarrow \mathrm{Z} \downarrow$ So, current increases $\&$ thus bulb will glow more brighter.
Asked in: JEE Main 2024 (09 Apr Shift 1)