A bucket containing water is revolved in a vertical circle of radius $r$ .To prevent the water from falling down, the minimum frequency of revolution required is ( $g=$ acceleration due to gravity)

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Aicharya · Accepted Answer

Let its angular velocity be $\omega$ at all points (uniform motion). At the highest point, weight of the body is balanced centrifugal force, so $\begin{aligned} & m \omega^2 r=m g \ & \Rightarrow \omega=\sqrt{\frac{g}{r}} \end{aligned}$ Angular frequency is related to frequency as follows: $\omega=2 \pi f$ $	herefore f=\frac{\omega}{2 \pi}=\frac{1}{2 \pi} \sqrt{\frac{g}{r}}$

A bucket containing water is revolved in a vertical circle of radius $r$ .To prevent the water from falling…

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