A boy pulls a toy cart across a flat room with a force of $5$ N, moving it over a distance of $4$ m. How…
A boy pulls a toy cart across a flat room with a force of $5$ N, moving it over a distance of $4$ m. How much work is done by the boy on the cart?
- $1$ J
- $9$ J
- $20$ J
- $0.8$ J
Solution
Work done is calculated as $\text{Force} \times \text{Distance}$. Here, $5\text{ N} \times 4\text{ m} = 20\text{ J}$.
Asked in: Homi Bhabha Practice
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