A box P contains one white ball, three red balls and two black balls. Another box Q contains two white balls…
- $\frac{29}{54}$
- $\frac{25}{42}$
- $\frac{35}{54}$
- $\frac{39}{52}$
Solution

P (Two different colour balls from each one of the boxes) $\begin{aligned} & =\mathrm{W}_{\mathrm{P}} \mathrm{R}_{\mathrm{Q}}+\mathrm{R}_{\mathrm{P}} \mathrm{~W}_{\mathrm{Q}}+\mathrm{R}_{\mathrm{P}} \mathrm{~B}_{\mathrm{Q}}+\mathrm{B}_{\mathrm{P}} \mathrm{R}_{\mathrm{Q}}+\mathrm{B}_{\mathrm{P}} \mathrm{~W}_{\mathrm{Q}}+\mathrm{W}_{\mathrm{P}} \mathrm{~B}_{\mathrm{Q}} \\ & =\frac{1}{6} \times \frac{3}{5}+\frac{3}{6} \times \frac{2}{5}+\frac{3}{6} \times \frac{4}{9}+\frac{2}{6} \times \frac{3}{5}+\frac{2}{6} \times \frac{2}{5}+\frac{1}{6} \times \frac{4}{9} \\ & =\frac{9}{54}+\frac{18}{54}+\frac{8}{54}=\frac{35}{54} \end{aligned}$
Asked in: AP EAMCET 2024 (20 May Shift 2)