A box of mass 5 kg is pulled by a cord, up along a frictionless plane inclined at $30^{\circ}$ with the…

A box of mass 5 kg is pulled by a cord, up along a frictionless plane inclined at $30^{\circ}$ with the horizontal. The tension in the cord is 30 N . The acceleration of the box is (Take $g=10 \mathrm{~m} \mathrm{~s}^{-2}$ )
  1. $2 \mathrm{~m} \mathrm{~s}^{-2}$
  2. Zero
  3. $0.1 \mathrm{~m} \mathrm{~s}^{-2}$
  4. $1 \mathrm{~m} \mathrm{~s}^{-2}$

Solution

$T-M g \sin 30=M a$
$30-5 \times 10 \times \frac{1}{2}=5 a$ $a=1 \mathrm{~m} / \mathrm{s}^2$

Asked in: NEET 2024 (Re-NEET)

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