A bomb of mass $16 \mathrm{~kg}$ at rest explodes into two pieces of masses of $4 \mathrm{~kg}$ and $12…

A bomb of mass $16 \mathrm{~kg}$ at rest explodes into two pieces of masses of $4 \mathrm{~kg}$ and $12 \mathrm{~kg}$. The velocity of the $12 \mathrm{~kg}$ mass is $4 \mathrm{~ms}^{-1}$. The kinetic energy of the other mass is
  1. $96 \mathrm{~J}$
  2. $144 \mathrm{~J}$
  3. $288 \mathrm{~J}$
  4. $192 \mathrm{~J}$

Solution

$m_1 v_1=m_2 v_2$ $\mathrm{KE}=\frac{1}{2} \mathrm{~m}_2 \mathrm{v}_2^2=\frac{1}{2} \times 4 \times 144=288 \mathrm{~J}$

Asked in: JEE Main 2006

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