A body starting from rest moving with an acceleration of $\frac{5}{4} \mathrm{~ms}^{-2}$. The distance travelled by the body in the third second is:

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Aicharya · Accepted Answer

$\mathrm{u}=0, \mathrm{a}=\frac{5}{4} \mathrm{~ms}^{-2}$ $S_{n t h}=u+(2 n-1) \frac{a}{2}$ $	herefore \quad \mathrm{S}_{3 \mathrm{rd}}=0+(2 	imes 3-1) 	imes \frac{5}{8}=\frac{25}{8} \mathrm{~m}$

A body starting from rest moving with an acceleration of $\frac{5}{4} \mathrm{~ms}^{-2}$. The distance…

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